Operator overloading with __add__

Question

Accepted Answer

The `+` operator calls `__add__`, which creates a new `Money` instance with the summed amounts. `print()` then calls `__str__`, which falls back to `__repr__` since `__str__` is not defined, producing `Money(35)`. Notice that `a + b` does not return a plain integer - it returns a `Money` object, which is the whole point of `__add__`: keeping the type consistent across operations.