Given an array nums containing n distinct numbers in the range [0, n], return the only number in the range that is missing from the array.
Input: nums = [3, 0, 1] Output: 2 Explanation: n = 3 since there are 3 numbers, so all numbers are in the range [0, 3]. 2 is the missing number since it does not appear in nums.
Input: nums = [0, 1] Output: 2 Explanation: n = 2 since there are 2 numbers, so all numbers are in the range [0, 2]. 2 is the missing number since it does not appear in nums.
Input: nums = [9, 6, 4, 2, 3, 5, 7, 0, 1] Output: 8 Explanation: n = 9 since there are 9 numbers, so all numbers are in the range [0, 9]. 8 is the missing number since it does not appear in nums.
1 <= nums.length <= 10^40 <= nums[i] <= nums.lengthnums are unique.nums = [3, 0, 1]